The prime 41, can be written as the sum of six consecutive primes:
\[41 = 2 + 3 + 5 + 7 + 11 + 13\]
This is the longest sum of consecutive primes that adds to a prime below one-hundred.
The longest sum of consecutive primes below one-thousand that adds to a prime, contains 21 terms, and is equal to 953.
Which prime, below one-million, can be written as the sum of the most consecutive primes?
连续素数的和
素数 41 可以写成六个连续素数的和：
\[41 = 2 + 3 + 5 + 7 + 11 + 13\]
在小于一百的素数中，41 能够被写成最多的连续素数的和。
在小于一千的素数中，953 能够被写成最多的连续素数的和，共包含连续 21 个素数。
在小于一百万的素数中，哪个素数能够被写成最多的连续素数的和？